Answer
The statement does not make sense.
Work Step by Step
The statement is false because the trigonometric function is defined in all quadrant angles.
For a quadrant angle $\theta =0$ ,
$\sin 0=0$
For a quadrant angle $\theta =\frac{\pi }{2}$ ,
$\sin \frac{\pi }{2}=1$
For a quadrant angle $\theta =\pi $ ,
$\sin \pi =0$
For a quadrant angle $\theta =\frac{3\pi }{2}$ ,
$\sin \frac{3\pi }{2}=-1$
Thus, the statement does not make sense.
