## Precalculus (6th Edition) Blitzer

Since $\pi \lt t \lt \frac{3\pi }{2}$, the point lies in the third quarter of the unit circle, so we have $\sin t \lt 0$ and $\cos t \lt 0$. Thus,$$\tan t = \frac{\sin t }{\cos t }\gt 0, \qquad \cot t =\frac{\cos t}{\sin t} \gt 0.$$