Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.1 - Angles and Radian Measure - Exercise Set - Page 533: 94

Answer

The required solution is $2.5\ \text{radians}$ or $143.23{}^\circ $

Work Step by Step

The radius of the earth $ r $ is $4000\ \text{miles}$. The distance $ s $ between A and B is $10,000\ \text{miles}$. The angle $\theta $ at the center between A and B is given by $\theta =\frac{s}{r}$ Put $10,000\ \text{miles}$ for $ s $ and $4000\ \text{miles}$ for $ r $: $\begin{align} & \theta =\frac{10,000\ \text{miles}}{4000\ \text{miles}} \\ & =2.5\ \text{radians} \end{align}$ Convert $\theta $ into degrees: $\begin{align} & \theta =2.5\ \text{radians}\left( \frac{180{}^\circ }{\pi \ \text{radians}} \right) \\ & =\left( \frac{2.5}{\pi } \right)180{}^\circ \end{align}$ Put $\pi =3.14159$: $\begin{align} & \theta =\left( \frac{2.5}{3.14159} \right)180{}^\circ \\ & =\left( 0.79577 \right)180{}^\circ \\ & =143.23{}^\circ \end{align}$
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