## Precalculus (6th Edition) Blitzer

$\frac{14\pi}{3}$ radians It is a positive angle and obtained by rotating the terminal side counterclockwise $\frac{14\pi}{3}$ = $4\pi$ + $\frac{2\pi}{3}$ radians. So $\frac{14\pi}{3}$ radians lies in quadrant II.