## Precalculus (6th Edition) Blitzer

$-150^{\circ}$
We have, radians $=\dfrac{-5\pi}{6}$ In order to find the result, we need to change radians into degrees by multiplying the given angle by $\dfrac{180}{\pi}$. $\dfrac{-5\pi}{6} \times \dfrac{180^{\circ}}{\pi}=-150^{\circ}$