Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Cumulative Review Exercises - Page 647: 8

Answer

$4x^2-\frac{14}{5}x-\frac{17}{25}+\frac{284}{25(5x+2)}$

Work Step by Step

Step 1. Write the division as $\frac{20x^3-6x^2-9x+10}{5x+2}=\frac{1}{5}\times\frac{20x^3-6x^2-9x+10}{x+2/5}$ Step 2. The question did not specify the method, so we can use the synthetic division as shown in the figure. Step 3. We have $\frac{20x^3-6x^2-9x+10}{5x+2}=\frac{1}{5}\times(20x^2-14x-\frac{17}{5}+\frac{284/25}{x+2/5})=4x^2-\frac{14}{5}x-\frac{17}{25}+\frac{284}{25(5x+2)}$
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