Answer
$y=191.9+24.569\ ln(x)$, $r=0.870$, see explanations.
Work Step by Step
Plot the data and use $y=a+b\ ln(x)$ to fit; we can get $a=191.9, b=24.569, r=0.870$, that is $y=191.9+24.569\ ln(x)$ as shown in the figure. As $r$ is between $0.5$ and $1$, it indicates a reasonably good fit (but not a great fit) using the model.
