Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.5 - Exponential Growth and Decay; Modeling Data - Exercise Set - Page 505: 6

Answer

In 2040

Work Step by Step

Given the model $ A=1173.1e^{0.008t}$, we solve for t when $ A=1491$ $ 1491=1173.1e^{0.008t}\qquad $... /$\div $1173.1 $\displaystyle \frac{1491}{1173.1}=e^{0.008t}\qquad $... $/\ln(...)$ $\displaystyle \ln\frac{1491}{1173.1}=0.008t\qquad $... /$\div 0.008$ $ t=\displaystyle \frac{\ln\frac{1491}{1173.1}}{0.008}\approx 29,97\approx 30$ years By this model, India will reach $1377$ million in 2040 (30 years from 2010).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.