## Precalculus (6th Edition) Blitzer

About $4$ grams
Model: $A=A_{0}e^{kt}$ $t=0$ for the year $2010.$ Unknown: $A$, when $A_{0}=16, t=11430,k=-0.000121t$ $A=A_{0}e^{kt}=16e^{-0.000121\cdot 11430}\approx 4.013$