## Precalculus (6th Edition) Blitzer

a)$$3$$ b)$$e^{x\ln 3}$$
a) Please note that according to the definition of the logarithm, we have $$b^{\log_bM}=M.$$ So, we have $$e^{\ln 3}=e^{\log_e 3}=3.$$ b) By part (a), we have$$3^x=(e^{\ln 3})^x=e^{x \ln 3}.$$