## Precalculus (6th Edition) Blitzer

$8.5$ years
Solve the given formula for $t.$ $A=Pe^{rt}\quad$ ... $/\div P$ $(A/P)=e^{rt}\quad$ ... $/\ln(...)$ $\ln(A/P)=rt\quad$ ... $/\div r$ $t=\displaystyle \frac{\ln(A/P)}{r}$ Insert the values given in the table. $t=\displaystyle \frac{\ln(25,000/17425)}{0.0425}\approx$8.4934 (round to 1 dec. place)