Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Concept and Vocabulary Check - Page 488: 7

Answer

$\displaystyle \frac{7x-23}{x+1}$

Work Step by Step

Logarithms are one-to-one, meaning that if $\log_{b}M=\log_{b}N,$ then $ M=N.$ Here, it follows that $\displaystyle \frac{7x-23}{x+1}=x-3$
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