Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set - Page 465: 118

Answer

$65.05$ decibels

Work Step by Step

We need to plug in the intensity level as given in the statement into the formula for decibels. We have $10 \log [(10^{12}) (3.2 \times 10^{-6})]$ Re-written as: $10 \log (3.2 \times 10^{6})$ Now, use a calculator to find the logarithmic value. So, we have $ 10 \log (3.2 \times 10^{6}) \approx 65.05$ decibels Our result is: $65.05$ decibels
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.