Answer
a. $ 4x^2-2x+7$
b. $ 8x^2-26x+26$
c. $ 8$
Work Step by Step
Given $f(x)=2x-3$ and $g(x)=2x^2-x+5$, we have:
a. $(f\circ g)(x)=2(2x^2-x+5)-3=4x^2-2x+7$
b. $(g\circ f)(x)=2(2x-3)^2-(2x-3)+5=8x^2-24x+18-2x+3+5=8x^2-26x+26$
c. $(g\circ f)(1)=8(1)^2-26(1)+26=8$
