Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 366: 80


a. $ 4x^2-2x+7$ b. $ 8x^2-26x+26$ c. $ 8$

Work Step by Step

Given $f(x)=2x-3$ and $g(x)=2x^2-x+5$, we have: a. $(f\circ g)(x)=2(2x^2-x+5)-3=4x^2-2x+7$ b. $(g\circ f)(x)=2(2x-3)^2-(2x-3)+5=8x^2-24x+18-2x+3+5=8x^2-26x+26$ c. $(g\circ f)(1)=8(1)^2-26(1)+26=8$
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