Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Concept and Vocabulary Check - Page 362: 1

Answer

For the long division problem $x+4\overline{\left){6x-4+2{{x}^{3}}}\right.}$ , begin the division process by rewriting the dividend as $2{{x}^{3}}+0{{x}^{2}}+6x-4$.

Work Step by Step

Consider, $x+4\overline{\left){6x-4+2{{x}^{3}}}\right.}$ We know that according to the general procedure for dividing one polynomial by another, we need to arrange the terms of the dividend and divisor in descending powers of $x$. So, the dividend $6x-4+2{{x}^{3}}$, which is not in descending powers of $x$ is replaced with: $2{{x}^{3}}+0{{x}^{2}}+6x-4$.
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