## Precalculus (6th Edition) Blitzer

$18; \\-15i; \\12i; \\-10i^2; \\10$
product of the first terms: $=3(6) \\=18$ product of the outside terms: $=3(-5i) \\=-15i$ product of the inside terms: $=2i(6) \\=12i$ product of the lest terms: $=2i(-5i) \\-10i^2$ Since $i^2=-1$, then $-10i^2= -10(-1)=10$ Therefore, the missing expressions in the given statements, in order are: $18; \\-15i; \\12i; \\-10i^2; \\10$