Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Review Exercises - Page 429: 19

Answer

a. maximum height at $x=20\ yards$ with $f(20)=16\ ft$ b. $6\ ft$ c. $ 45.3\ yards$ d. See graph

Work Step by Step

a. Given $f(x)=-0.025x^2+x+6=-0.025(x^2-40x+400)+10+6=-0.025(x-20)^2+16$ we can identify a maximum height at $x=20\ yard$ with $f(20)=16\ ft$ b. The initial height is given at $x=0$ with $f(0)=6\ ft$ c. Let $f(x)=0$; we have $-0.025(x-20)^2+16=0$, which gives $x=20\pm\sqrt {640}$ and $x\approx45.3\ yard$ (discard negative answer). d. See the graph of the function.
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