Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Cumulative Review Exercises - Page 435: 20

Answer

$4x+2h-1$

Work Step by Step

Step 1. Given $f(x)=2x^2−x−1$, we have $f(x+h)=2(x+h)^2-(x+h)-1=2x^2+4xh+2h^2-x-h-1$ Step 2. We have: $f(x+h)-f(x)=4xh+2h^2-h$ Step 3. We have: $\frac{f(x+h)-f(x)}{h}=\frac{4xh+2h^2-h}{h}=4x+2h-1$
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