## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 11 - Section 11.3 - Limits and Continuity - Exercise Set - Page 1162: 45

#### Answer

See below for answers and explanations.

#### Work Step by Step

a. Based on the given piece-wise function, we have $\lim_{x\to8500^-}T(x)=0.1(8500)=850$ and $\lim_{x\to8500^+}T(x)=850+0.15(8500-8500)=850$ Since $T(x)$ is defined at $x=8500$ and the left and right limits exist and are equal to the function value, we conclude that $T$ is continuous at $8500$. b. We have $\lim_{x\to34500^-}T(x)=850+0.15(34500-8500)=4750$ and $\lim_{x\to34500^+}T(x)=4750+0.25(34500-34500)=4750$ Since $T(x)$ is defined at $x=34500$ and the left and right limits exist and are equal to the function value, we conclude that $T$ is continuous at $34500$. c. If $T$ contains discontinuities, it is possible that a person with a higher earning pays too much tax and that he ends up getting less money in his pocket than another person with a lower earning who pays less tax.

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