Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.1 - Finding Limits Using Tables and Graphs - Exercise Set - Page 1140: 56

Answer

$$(f \circ g)(x)=(\sqrt{x})^2+3=x+3$$ $$\lim_{x \to 1 }(f \circ g)(x)=4$$
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Work Step by Step

To find $\lim_{x\to 1 }(f \circ g)(x)$, examine the graph of $f \circ g$ near $x=1$. As $x$ gets closer to $1$, the values of $(f \circ g)(x)$ get closer to $4$. We conclude from the graph that$$\lim_{x \to 1 }(f \circ g)(x)=4.$$
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