Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.1 - Finding Limits Using Tables and Graphs - Exercise Set - Page 1139: 39

Answer

See below:
1571114504

Work Step by Step

Consider the function $ y=\frac{1}{x}$, For $\underset{x\to -{{1}^{-}}}{\mathop{\lim }}\,f\left( x \right)$, Approach the point $ x=-1$ on the graph from the left side; the value of the $ y-$ coordinate approaches to $-1$. So, $\underset{x\to -{{1}^{-}}}{\mathop{\lim }}\,f\left( x \right)=-1$, For $\underset{x\to -{{1}^{+}}}{\mathop{\lim }}\,f\left( x \right)$, Now approach the point from the right side. As the point is reached, the value of the $ y-$ coordinate approaches to $-1$. So, $\underset{x\to -{{1}^{+}}}{\mathop{\lim }}\,f\left( x \right)=-1$, Since, $\underset{x\to -{{1}^{+}}}{\mathop{\lim }}\,f\left( x \right)=\underset{x\to -{{1}^{-}}}{\mathop{\lim }}\,f\left( x \right)=-1$, the value for the given limit exists and is given by, $\underset{x\to -1}{\mathop{\lim }}\,\frac{1}{x}=-1$
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