## Precalculus (6th Edition) Blitzer

$\lim_\limits{x\to 0}\frac{\sin 3x}{x}=3$
To find the limit using the table, we must find the value that $f(x)$ approaches, as $x$ approaches a given value. Here, we are asked to find the limit as $x\to0$. As $x$ approaches $0$ from both sides, it is clear that the values of $f(x)$ are approaching $3$. Thus, $\lim_\limits{x\to 0}\frac{\sin 3x}{x}=3$.