Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Review Exercises - Page 1178: 3

Answer

$2$

Work Step by Step

We need to build a table that shows the values of $x$ close to $0$ from the left and right sides and the values of $f(x)$ for those values of $x$. $ x= -0.1..........., x= 0.111111$ This gives: $ f(x)= 1.986693308,......f(x)= 1.983579724$ From the table, we have $\lim_\limits {x \to 0} \dfrac{\sin 2x}{x}=2$
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