Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.5 - The Binomial Theorum - Concept and Vocabulary Check - Page 1092: 3

Answer

The required solution is $\left( \begin{align} & n \\ & r \\ \end{align} \right)=\underline{\frac{n!}{r!\left( n-r \right)!}}$

Work Step by Step

We know that for non-negative integers n and r, with$n\ge r$, the expression $\left( \begin{align} & n \\ & r \\ \end{align} \right)$ (read as “n above r”) is called the binomial coefficient and is defined by: $\left( \begin{align} & n \\ & r \\ \end{align} \right)=\frac{n!}{r!\left( n-r \right)!}$
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