Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.4 - Mathematical Induction - Concept and Vocabulary Check - Page 1084: 5


${{k}^{2}}+3k+2=\left( {{k}^{2}}+k \right)+2$ $\left( k+1 \right)$

Work Step by Step

Solving, we get $\begin{align} & {{k}^{2}}+3k+2={{k}^{2}}+k+2k+2 \\ & ={{k}^{2}}+k+2\left( k+1 \right) \\ & =\left( {{k}^{2}}+k \right)+2\left( k+1 \right) \end{align}$
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