Answer
The first term of $\sum\limits_{i=1}^{20}{\left( 6i-\text{ }4 \right)}$ is 2 and the last term is 116.
Work Step by Step
To find the first term, we will substitute $ i=1$ in the given equation
$\begin{align}
& 6i-4=6\left( 1 \right)-4 \\
& =6-4 \\
& =2
\end{align}$
To find the last term, we will substitute $ i=20$ in the given equation
$\begin{align}
& 6i-4=6\left( 20 \right)-4 \\
& =120-4 \\
& =116
\end{align}$
