Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Review Exercises - Page 1126: 97

Answer

The probability is $\frac{1}{32}$.

Work Step by Step

We know that the probability of having one boy is given below, $\text{P}\left( \text{one boy} \right)=\text{ }\frac{1}{2}$ And probability of having five boys in a row is: $\begin{align} & P\left( \text{five boys in a row} \right)=P\left( \text{one boy} \right)\times P\left( \text{one boy} \right)\times P\left( \text{one boy} \right)\times P\left( \text{one boy} \right)\times P\left( \text{one boy} \right) \\ & =\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2} \\ & =\frac{1}{32} \end{align}$
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