## Precalculus (6th Edition) Blitzer

The probability is $\frac{1}{32}$.
We know that the probability of having one boy is given below, $\text{P}\left( \text{one boy} \right)=\text{ }\frac{1}{2}$ And probability of having five boys in a row is: \begin{align} & P\left( \text{five boys in a row} \right)=P\left( \text{one boy} \right)\times P\left( \text{one boy} \right)\times P\left( \text{one boy} \right)\times P\left( \text{one boy} \right)\times P\left( \text{one boy} \right) \\ & =\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2} \\ & =\frac{1}{32} \end{align}