#### Answer

$(x-3)^2+(y-2)^2=25$
Refer to the step-by-step part below for explanation.

#### Work Step by Step

The circle $(x-3)^2 + (y-2)^2=25$ is in standard form.
The standard form of a circles equation is $(x-h)^2 + (y-k)^2=r^2$ where $(h,k)$ is the center and $r$ is the radius.
Given an equation in standard form, the values of h and k can be determined by simply taking the "opposite" of the number you see beside x and y.
To illustrate:
In the given example above, since what you have are:
$(x-3)^2$, it means that $h=3$, the "opposite of $-3$.
$(y-2)^2$, it means that $k=2$, the "opposite" of $-2$.
If the equation is $(x+3)^2 + (y-7)^2=25$, then
$h = -3$ (the opposite of 3) and $k=7$ (the opposite of 7).
The value of $r$ can be determined by simply taking the square root of the constant found on the right side.