## Precalculus (6th Edition) Blitzer

$\dfrac{f(x)}{g(x)}; \text{ } g(x)$
RECALL: $\left(\dfrac{f}{g}\right)(x) = \dfrac{f(x)}{g(x)}$, where $g(x) \ne 0$ since division of zero is not allowed. Thus, the missing expressions in the given statement are: $\dfrac{f(x)}{g(x)}; \text{ } g(x)$