## Precalculus (6th Edition) Blitzer

$y-y_1=m(x-x_1)$
RECALL: The point-slope form of a line's equation is: $y-y_1=m(x-x_1)$ where m = slope and $(x_1, y_1)$ is a point on the line. Thus, the missing expression in the given statement is: $y-y_1=m(x-x_1)$