## Precalculus (6th Edition) Blitzer

a. $g(0)=3$ b. $g(-6)=3$ c. $g(-3)=0$
a. Given the piecewise function $g(x)=\begin{cases} x+3,\hspace{1.2cm} x\geq-3 \\ -(x+3),\hspace{0.5cm} x\lt-3 \end{cases}$ we can identify that $g(0)=0+3=3$ b. $g(-6)=-(-6+3)=3$ c. $g(-3)=-3+3=0$