Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.2 - Basics of Functions and Their Graphs - Exercise Set - Page 179: 106

Answer

The value of the car as a function of x is $V(x)=22,500-3200x,\text{ }0\le x\le 6$, and $V\left( 3 \right)=\$12,900$, which means that the value of the car after 3 years is $\$12,900$.

Work Step by Step

Suppose the value of the car after x years is $V\left( x \right)$, where $0\le x\le 6$. Since the value of the car is decreased by $\$3200$ , the value of the car after x years is given as follows: $V\left( x \right)=22,500-3200x,\,\,0\le x\le 6$ Put $x=3$ in the above equation to get the value of the car after 3 years: $\begin{align} & V\left( 3 \right)=22,500-3200\times 3 \\ & =22,500-9600 \\ & =12,900 \end{align}$ So, the value of the car after 3 years is $\$12,900$. Thus, the value of the car as a function of x is $V(x)=22,500-3200x,\text{ }0\le x\le 6$ , and the value of car after 3 years is $V\left( 3 \right)=\$12,900$
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