Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.2 - Basics of Functions and Their Graphs - Exercise Set - Page 178: 95

Answer

The value of the given expression is $-38$

Work Step by Step

Substitute the value of the functions as given in the table to obtain the following expression $\begin{align} & \sqrt{f\left( -1 \right)-f\left( 0 \right)}-{{\left[ g\left( 2 \right) \right]}^{2}}+f\left( -2 \right)\div g\left( 2 \right)\cdot g\left( -1 \right)=\sqrt{3-\left( -1 \right)}-{{\left[ -6 \right]}^{2}}+6\div \left( -6 \right)\cdot 4 \\ & =\sqrt{4}-36+\left( -1 \right)\cdot 4 \\ & =2-36-4 \\ & =-38 \end{align}$ Therefore, the value of the expression is: $\sqrt{f\left( -1 \right)-f\left( 0 \right)}-{{\left[ g\left( 2 \right) \right]}^{2}}+f\left( -2 \right)\div g\left( 2 \right)\cdot g\left( -1 \right)=-38$.
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