## Precalculus (6th Edition) Blitzer

a. $f(x)=300+0.7x$ b. $g(x)=40+0.9x$ c. $1300$ dollars, $1210$ dollars.
a. For plan A, the annual price is $f(x)=300+0.7x$ where $x$ is the dollars of merchandise purchased. b. For plan B, the annual price is $g(x)=40+0.9x$ where $x$ is the dollars of merchandise purchased. c. Let the above cost to be equal, we have $300+0.7x=40+0.9x$ which gives $0.2x=260$ and $x=1300$ dollars. The total would be $f(1300)=300+0.7(1300)=1210$ dollars.