## Precalculus (6th Edition) Blitzer

Yes, the graph of ${{Y}_{1}}$ passes through the origin.
The table above shows different values x for different values of y. The provided table represents the value of ${{y}_{1}}=0$ when $x=0$. And for the graph to be passing through the origin, the equation of the graph must have passed through $\left( 0,0 \right)$. Therefore, the graph of ${{y}_{1}}$ passes through the origin.