#### Answer

Refer to the image below for the graph.

#### Work Step by Step

RECALL:
The point $(x, y)$ has:
$x$ = directed distance of the point from the y-axis (positive when to the right of the y-axis, negative when to the left)
$y$ = directed distance of the point from the x-axis (positive when above the x-axis, negative when below)
Thus, the given point is:
$\dfrac{5}{2}$ units to the left of the y-axis
$\dfrac{3}{2}$ units above the x-axis
(refer to the attached image in the answer portion for the graph)