Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.1 - Graphs and Graphing Utilities - Concept and Vocabulary Check - Page 158: 6


solution; satisfies

Work Step by Step

Substituting 4 to $x$ in $y=x^2+3$ gives: $y=x^2+3 \\y=4^2+3 \\y=16+3 \\y=19$ Thus, the point $(4, 19)$ is a solution of $y=x^2+3$. So $(4, 19)$ satisfies the equation. Therefore, the missing expressions in the given statements are : solution; satisfies
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