Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Review Exercises - Page 304: 121

Answer

$(-\frac{11}{2},-2)$

Work Step by Step

Given the coordinates of the two end points as $(4,-6)$ and $(-15,2)$, using the formula for midpoint, we have $x_m=\frac{4-15}{2}=-\frac{11}{2}$ and $y_m=\frac{-6+2}{2}=-2$, which gives the midpoint as $(-\frac{11}{2},-2)$
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