## Precalculus (6th Edition) Blitzer

Any value of $x$ can be used in the equation $f\left( x \right)={{x}^{2}}-4$. Select five of the possible values $x=\left( -2,-1,0,1,2 \right)$ and put into equation $f\left( x \right)={{x}^{2}}-4$. If we put $x=-2$: \begin{align} & f\left( x \right)={{\left( -2 \right)}^{2}}-4 \\ & f\left( x \right)=4-4 \\ & f\left( x \right)=0 \\ \end{align} And if we put $x=-1$: \begin{align} & f\left( x \right)={{\left( -1 \right)}^{2}}-4 \\ & f\left( x \right)=1-4 \\ & f\left( x \right)=-3 \\ \end{align} And if we put $x=0$: \begin{align} & f\left( x \right)={{\left( 0 \right)}^{2}}-4 \\ & f\left( x \right)=0-4 \\ & f\left( x \right)=-4 \\ \end{align} And we if put $x=1$: \begin{align} & f\left( x \right)={{\left( 1 \right)}^{2}}-4 \\ & f\left( x \right)=1-4 \\ & f\left( x \right)=-3 \\ \end{align} And we if put $x=2$: \begin{align} & f\left( x \right)={{\left( 2 \right)}^{2}}-4 \\ & f\left( x \right)=4-4 \\ & f\left( x \right)=0 \\ \end{align} Draw the curve that passes through these points $\left( -2,0 \right),\left( -1,-3 \right),\left( 0,-4 \right),\left( 1,-3 \right),\left( 2,0 \right)$.