Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Mid-Chapter Check Point - Page 228: 8


$y$ is not a function of $x$

Work Step by Step

Solve for $y$ in terms of $x$ to obtain: $y^2=-x+5 \\y = \pm \sqrt{-x+5}$ Note that each value of $x$ within the relation's domain will give one or two values of $y$. Thus, the given equation does not represent $y$ as a function of $x$.
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