Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - Chapter Review - Chapter Test - Page 559: 11

Answer

$61.0^\circ$

Work Step by Step

Use $\sin{\theta} = \frac{\text{opposite}}{\text{hypotensue}}$ to obtain $\sin{(\theta)}=\frac{10.5}{12}=0.875.$ Use inverse sine to find the value of $\theta$: $\theta=\sin^{-1}{(0.875)}\approx 61.0^\circ$
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