## Precalculus (10th Edition)

$61.0^\circ$
Use $\sin{\theta} = \frac{\text{opposite}}{\text{hypotensue}}$ to obtain $\sin{(\theta)}=\frac{10.5}{12}=0.875.$ Use inverse sine to find the value of $\theta$: $\theta=\sin^{-1}{(0.875)}\approx 61.0^\circ$