Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - Chapter Review - Chapter Test - Page 559: 10


$19.81$ square units

Work Step by Step

Using Heron's formula, the area $A$ of a triangle is $A=\sqrt{s(s-a)(s-b)(s-c)}$, where $s=\frac{a+b+c}{2}.$ Hence, here we have $s=\frac{5+8+10}{2}=11.5$, Thus, $A=\sqrt{11.5(11.5-5)(11.5-8)(11.5-10)}\approx19.81$
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