Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.1 Right Triangle Trigonometry; Applications - 8.1 Assess Your Understanding - Page 520: 54

Answer

$\approx20.7\text{ ft}.$

Work Step by Step

We know that $\sin{\theta}=\frac{\text{opposite}}{\text{hypotenuse}}$. We can denote that $\sin{(70^o)}=\frac{d}{22}$, hence $d=20\sin{(70^o)}\approx20.7\text{ ft}.$
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