Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.1 Right Triangle Trigonometry; Applications - 8.1 Assess Your Understanding - Page 520: 52

Answer

$\approx214.5\text{ ft}$

Work Step by Step

We know that $\tan{\theta}=\frac{\text{opposite}}{\text{adjacent}}$. We can denote that $\tan{(25^o)}=\frac{100}{d}$, hence $d=\frac{100}{\tan{(25^o)}}\approx214.5\text{ ft}$
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