Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.5 Sum and Difference Formulas - 7.5 Assess Your Understanding - Page 489: 109

Answer

See below.

Work Step by Step

Step 1. Using the given figure, we have $\theta_2=\theta+\theta_1$, thus $\theta=\theta_2-\theta_1$ Step 2. We have $tan\theta=tan(\theta_2-\theta_1)=\frac{tan(\theta_2)-tan(\theta_1)}{1+tan(\theta_2)tan(\theta_1)}=\frac{m_2-m_1}{1+m_1m_2}$
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