Answer
$|A|=2$, $p=\pi$, $\phi=\frac{\pi}{2}$.
See graph.
Work Step by Step
Step 1. Given $y=2sin(2x-\pi)=2sin(2(x-\frac{\pi}{2}))$, we can identify its amplitude $|A|=2$, period $p=\frac{2\pi}{2}=\pi$, phase shift $\phi=\frac{\pi}{2}$
Step 2. See graph.
