Answer
$\frac{9\pm\sqrt {17}}{4}$
Work Step by Step
$f(x)=0 \longrightarrow 2x^2-9x+8=0 \longrightarrow x=\frac{9\pm\sqrt {9^2-4(2)(8)}}{2(2)}=\frac{9\pm\sqrt {17}}{4}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.3 Trigonometric Equations - 7.3 Assess Your Understanding - Page 470: 124
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