Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.1 The Inverse Sine, Cosine, and Tangent Functions - 7.1 Assess Your Understanding - Page 450: 9


$-\frac{\pi}{2}\lt x\lt\frac{\pi}{2}.$

Work Step by Step

$\tan^{-1}(\tan(x))=x$ where $-\frac{\pi}{2}\lt x\lt\frac{\pi}{2}.$ (as this is the range of $f(x)=\tan^{-1}(x).$)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.