Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.1 The Inverse Sine, Cosine, and Tangent Functions - 7.1 Assess Your Understanding - Page 450: 5

Answer

$1$, $\frac{\sqrt3}{2}$

Work Step by Step

$\tan{\frac{\pi}{4}}=\tan{45^\circ}=1$, $\sin{\frac{\pi}{3}}=\sin{60^\circ}=\frac{\sqrt3}{2}$
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