Answer
$(x)^2+(y+2)^2=4^2.$
Work Step by Step
The standard equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$, hence our equation: $(x-0)^2+(y-(-2))^2=4^2$, which is: $(x)^2+(y+2)^2=4^2.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - Chapter Review - Cumulative Review - Page 437: 3
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